gill
UGC Junior Addict
Posts: 384
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Post by gill on May 12, 2014 8:42:55 GMT -5
For me:
Rattlesnke X1 = 4 Cole de watson and Watsonberg X 1 each = 4 Watsonburg X 1 = 2 Watsonburg x 5 = 10 _________________________________________
20 (new) + 11 = 31 Total
For Chriso:
5 x Watsonburg = 10 Rattlesnke X1 = 4 Cole de watson and Watsonberg X 1 each = 4 __________________________________________
18 (new) + 6 = 24 Total
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Post by chriso on May 14, 2014 15:52:34 GMT -5
once more up watson for me =26
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andrewm
UGC Junior Addict
Posts: 458
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Post by andrewm on May 15, 2014 9:28:36 GMT -5
1x Watson 1x Col de Watson
17 + (2x2) = 21
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gill
UGC Junior Addict
Posts: 384
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Post by gill on May 21, 2014 11:34:23 GMT -5
5x Watson = 10 _____________________ New total: 41
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Post by chriso on May 22, 2014 16:09:24 GMT -5
1x Watson=2 total 28
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gill
UGC Junior Addict
Posts: 384
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Post by gill on May 26, 2014 11:53:14 GMT -5
Watson X 5 = 10 ___________________
New Total = 51
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